WBPSC recruitment 2019: West Bengal Public Service Commission (WBPSC) has issued a recruitment notification inviting applications for 200 Livestock Development Assistant posts. The candidates will be able to apply before June 3, 2019. They have to apply in the prescribed format for these posts by the last date. The form submission process starts from today. 

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The applicants must read the official notification before applying for these posts to make sure that they have all the educational qualifications and experience for these posts. The candidates who do not meet the requisite eliligibility criteria, will not be considered for these jobs.

WBPSC recruitment 2019: Vacancy details:
Livestock Development Assistant: 200 posts

WBPSC recruitment 2019: Educational qualification:
The candidates should have passed Madhyamik Examination from the West Bengal Board of Secondary Education or its equivalent.  They must have passed one year’s certificate course on Prani Sampad Bikash Prashikhan provied by the Board of Veterinary Education, West Bengal or its equivalent recognised by the Board of Veterinary Education, West Bengal. The candidates should be physically fit and capable of doing hard work and cycling.

WBPSC recruitment 2019: Age Limit:
The candidates should not be more than 40 years of age as of January 1, 2019. 
Salary:  
The candidates will be recruited in (PB – 2) Rs 5,400 - Rs. 25,200 with a Grade Pay of Rs 2,600.
How to apply: 
The candidates can apply through WBPSC official website - pscwbapplication.in - by June 3, 2019. They should apply early to avoid a last-minute rush. The applicants have to make sure that there is no mistake in the application. They have to follow the instructions given in the official notification while applying for these posts. The candidates should keep all the documents at hand while filling in the application form to avoid any misinformation.